QuestionAnswer the questions below based off this information: The… One-Sample Statistics N Mean Std. Deviation S.E. Mean Competition Anxiety Score 16 55.27 14.98 3.74One-Sample Test Test Value = 50 95% Confidence Interval of the Difference df Sig. (2-tailed) Mean DifferenceLower Upper Competition Anxiety Score 1.41 15 .180 5.27 -2.71 13.25… Show moreAnswer the questions below based off this information:The population of interest was high school age players who played for teams in the 2019 St. Louis Youth Soccer Association, prior to the pandemic.The researcher was interested in investigating two variables (1) the players’ self-rating on Competition Anxiety and (2) the players’ Coaches’ Rating of How Well an Athlete Performs under Pressure. The researcherrandomly selected 16 players and collected data on the two variables mentioned above.The researcher knows that, based on norm data, the average score on the Competition Anxiety Scale is 50 for a large cross section of American adolescents. He wants to know if the St. Louis soccer players are more anxious about competition than the typical American teenager.Null – The mean anxiety score of St. Louis soccer players is equal or less than 50Alternative -The mean anxiety score of St. Louis soccer players is more than 50One tailThe sample size is very small (<30); hence this will not work for a Z-test. Use T-test instead.1. What is your conclusion (fail to reject null hypothesis or reject null hypothesis)?2. What does this tell us about the Competition Anxiety of the population of St. Louis high school soccer players (compared to the typical American adolescent)?3. For Competition Anxiety, are we in danger of a Type 1 or Type 2 error?MathStatistics and Probability PY 571
solved : QuestionAnswer the questions below based off this informatio
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